Structure of the Atom
Introduction
Atomic structure is a story of evidence refining models. The guide moves from Rutherford scattering and nuclear notation to spectra, photons, nuclear size, and the Bohr model at HL.
Guide Focus
- Explain the Geiger-Marsden-Rutherford experiment and nuclear notation.
- Use spectra as evidence for discrete atomic energy levels.
- Apply HL nuclear radius, distance of closest approach, and Bohr-model ideas.
Key Concepts
1. Rutherford scattering
Most alpha particles passed through thin gold foil, but a few scattered through large angles. This showed that atoms contain a tiny, dense, positively charged nucleus.
2. Nuclear notation
A nucleus is described by chemical symbol X, proton number Z, and nucleon number A. A gives protons plus neutrons; Z gives protons.
3. Spectra and photons
Emission and absorption spectra provide evidence for discrete atomic energy levels. A photon is emitted or absorbed when an electron changes energy level, with photon energy E = hf.
4. HL nuclear and Bohr models
Nuclear radius follows R = R0 A^(1/3), implying approximately constant nuclear density. The Bohr model for hydrogen uses En = -13.6/n^2 eV and quantized angular momentum mvr = nh / (2pi).
Common Mistakes
- Confusing nucleon number with neutron number.
- Treating spectra as continuous rather than discrete line patterns.
- Forgetting that higher n levels in hydrogen are less negative and closer to zero energy.
Exam Tips
- For photon transitions, use energy difference, not absolute level alone.
- Rutherford distance of closest approach uses energy conservation.
- Spectral lines can identify chemical composition because each element has a characteristic pattern.
Practice Questions
Question 1 (Multiple Choice)
Line emission spectra provide evidence that atomic energy levels are:
A. Discrete. B. Continuous. C. Randomly changing. D. All identical for every element.
Solution Architecture
Only certain photon energies are emitted, showing that atomic energy changes are quantized.
Question 2 (Structured Paper 2 Style)
An electron in hydrogen moves from n = 3 to n = 2. The levels are E3 = -1.51 eV and E2 = -3.40 eV.
(a) Calculate the photon energy in eV. [2 marks]
(b) State whether the photon is emitted or absorbed. [1 mark]
Markscheme Breakdown
Part (a) Solution:
Photon energy = E3 - E2 = -1.51 - (-3.40) = 1.89 eV.
Part (b) Solution:
The electron moves to a lower energy level, so a photon is emitted.