Induction
Introduction
Electromagnetic induction is how changing magnetic conditions generate emf. The guide frames Faraday’s law and Lenz’s law as both a calculation method and a direct consequence of energy conservation.
Guide Focus
- Use magnetic flux Phi = BA cos(theta).
- Apply Faraday’s law epsilon = -N delta Phi / delta t.
- Use Lenz’s law and motional emf epsilon = BvL.
Key Concepts
1. Magnetic flux
Magnetic flux measures how much magnetic field passes through an area: Phi = BA cos(theta). The angle is between the magnetic field and the normal to the area.
2. Faraday’s law
A changing magnetic flux induces an emf: epsilon = -N delta Phi / delta t. More turns, faster change, stronger field, or larger area can increase the magnitude.
3. Lenz’s law
The induced emf acts in a direction that opposes the change causing it. This is required by conservation of energy.
4. Motional and generator emf
A straight conductor moving perpendicular to a uniform magnetic field has epsilon = BvL. A coil rotating in a uniform magnetic field produces sinusoidally varying emf, and increasing rotation frequency increases the induced emf.
Common Mistakes
- Using the angle to the plane of the coil instead of the angle to the normal.
- Ignoring the minus sign as a direction statement from Lenz’s law.
- Assuming a steady magnetic flux induces emf.
Exam Tips
- Ask what quantity is changing: B, A, angle, or time.
- For direction questions, identify the original change, then oppose it.
- For rectangular coils entering or leaving fields, track how the area inside the field changes.
Practice Questions
Question 1 (Multiple Choice)
A coil sits in a constant uniform magnetic field with no motion. The magnetic flux is constant. The induced emf is:
A. Zero. B. Maximum. C. Equal to BA. D. Equal to BvL.
Solution Architecture
Induced emf requires a rate of change of flux. If flux is constant, delta Phi / delta t = 0.
Question 2 (Structured Paper 2 Style)
A straight conductor of length 0.25 m moves at 4.0 m s-1 perpendicular to a 0.50 T magnetic field.
(a) Calculate the induced emf. [2 marks]
(b) State one way to double the emf. [1 mark]
Markscheme Breakdown
Part (a) Solution:
epsilon = BvL = 0.50 x 4.0 x 0.25 = 0.50 V.
Part (b) Solution:
Double B, v, or L while keeping the motion perpendicular.